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Subject Ugh
     
Posted by lazer(NV) on January 17, 2010 at 1:35 PM
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In Reply To The solenoid will not charge with an *open* circuit posted by BobbyT on January 17, 2010 at 04:28 AM
     
Message You're understanding of electronics is very elementary. Every electronic component is posses an inductance, capacitance, and resistance. This is true for even simple wires. Let me list where your thinking is correct:

1) Voltage 'level' isn't as important as voltage differences. This is true, it's the electric field that does the work not the electrostatic potential.

2) A solenoid cannot build magnetic field without a current flowing through it. This is correct also.

Now realize this. The solenoid (loop of wire) is always connected to a positive voltage source (I believe it's a +5V source). Yes the circuit is normally open and when the ECU closes the circuit (grounds it) the current flows and the injector fires. Also realize that the fuel rail and thus the body of the injector is grounded (attached to the negative terminal of the battery). So if you measure the voltage difference between the body of the injector and the coil (with the injector circuit open, not firing) you'd measure a voltage difference. This difference is present across the fuel and resin in the injector. This produces an electric field across the fuel and resin.

I encourage you to pick up some physics textbooks and read up a bit more. I suggest Foundations of Electromagnetic Theory by Reitz and Electrodynamics by Griffiths.




"The 300ZX Turbo is a dance; it's a song; it's rolling, roaring automotive art. There is no color that doesn't suit it. There is no mood-lifting chemical substance it can't replace." - Automobile Magazine

     
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